LOL Pic Thread (NO POLITICS)

shoei · 10-05-2021, 05:18 PM

.

Buug959 · 10-05-2021, 05:35 PM

Quote:

Originally Posted by shoei

They must also weigh the same as a stack of bricks judging from the damage lol.

Adults average between 2.6 and 6.5kgs (5.7 to 14.3 lbs) so yeah, they pack a punch at 100km/h.

shoei · 10-05-2021, 05:37 PM

Quote:

Originally Posted by LemansE90335xi

Quote:

Originally Posted by shoei

They must also weigh the same as a stack of bricks judging from the damage lol.

Adults average between 2.6 and 6.5kgs (5.7 to 14.3 lbs) so yeah, they pack a punch at 100km/h.

It actually fell from a power line but I guess velocity lol

shoei · 10-05-2021, 06:09 PM

,

Esteban · 10-05-2021, 06:18 PM

Quote:

Originally Posted by shoei

,

Nailed it!

Joe T · 10-05-2021, 06:32 PM

Quote:

Originally Posted by Lady Jane

Now I want to see the wrench.

Attachment 2712379

those guys have HUGE Nuts

kb2wji · 10-05-2021, 06:54 PM

Quote:

Originally Posted by Joe T

Quote:

Originally Posted by Lady Jane

Now I want to see the wrench.

Attachment 2712379

those guys have HUGE Nuts

.... two drums and a symbol fall off the roof

shoei · 10-05-2021, 07:05 PM

'

wtwo3 · 10-05-2021, 07:42 PM

Quote:

Originally Posted by shoei

It actually fell from a power line but I guess velocity lol

I'm not a physicist but I'm feeling wild this evening. Let's do this....

Assumptions:
- power line height of 4.5 meters
- car windshield height of 1.4 meters
- goose weight of 6.5 kg
- the goose caused a 5cm deep indentation into the windshield

We will calculate a couple things:
- speed upon impact
- force of impact upon windshield

V = sqrt(2*g*h)
Where:
V = velocity at impact
g = acceleration (in this case gravity)
h = distance (in this case height)

So... v = sqrt(2*9.8*3.1) = 7.795 m/s = 17.4 mph

Next...

F = (m*g*h)/d
Where:
F = force
M = mass
G = gravity
H = height
D = distance (in this case the distance the goose moved the windshield as a result of the impact)

So... F = (6.5*9.8*3.1)/0.05 = 3,949 N = 887 lbs

Upon further research, the average force required to break a car windshield is 9,400 psi.

So what's the lesson here? Absolutely nothing.

sygazelle · 10-05-2021, 07:50 PM

Quote:

Originally Posted by shoei

How you know to pack it in and call it a day.

That windshield is getting smashed on Grey Goose.

kscarrol · 10-05-2021, 08:13 PM

Quote:

Originally Posted by wtwo3

I'm not a physicist but I'm feeling wild this evening. Let's do this....

Assumptions:
- power line height of 4.5 meters
- car windshield height of 1.4 meters
- goose weight of 6.5 kg
- the goose caused a 5cm deep indentation into the windshield

We will calculate a couple things:
- speed upon impact
- force of impact upon windshield

V = sqrt(2*g*h)
Where:
V = velocity at impact
g = acceleration (in this case gravity)
h = distance (in this case height)

So... v = sqrt(2*9.8*3.1) = 7.795 m/s = 17.4 mph

Next...

F = (m*g*h)/d
Where:
F = force
M = mass
G = gravity
H = height
D = distance (in this case the distance the goose moved the windshield as a result of the impact)

So... F = (6.5*9.8*3.1)/0.05 = 3,949 N = 887 lbs

Upon further research, the average force required to break a car windshield is 9,400 psi.

So what's the lesson here? Absolutely nothing.

Murf993 Sounds like the rum is talking here...

DieselOG · 10-05-2021, 09:29 PM

,

Murf993 · 10-05-2021, 09:31 PM

Quote:

Originally Posted by kscarrol

Murf993 Sounds like the rum is talking here...

You beat me to it.

Murf993 · 10-05-2021, 09:34 PM

Quote:

Originally Posted by wtwo3

I'm not a physicist but I'm feeling wild this evening. Let's do this....

Assumptions:
- power line height of 4.5 meters
- car windshield height of 1.4 meters
- goose weight of 6.5 kg
- the goose caused a 5cm deep indentation into the windshield

We will calculate a couple things:
- speed upon impact
- force of impact upon windshield

V = sqrt(2*g*h)
Where:
V = velocity at impact
g = acceleration (in this case gravity)
h = distance (in this case height)

So... v = sqrt(2*9.8*3.1) = 7.795 m/s = 17.4 mph

Next...

F = (m*g*h)/d
Where:
F = force
M = mass
G = gravity
H = height
D = distance (in this case the distance the goose moved the windshield as a result of the impact)

So... F = (6.5*9.8*3.1)/0.05 = 3,949 N = 887 lbs

Upon further research, the average force required to break a car windshield is 9,400 psi.

So what's the lesson here? Absolutely nothing.

I'm going to suggest that the goose was hit by the moving vehicle for two reasons, I've never seen a goose sitting on hydro wires or in a tree for that matter and two I've seen a goose go through a car windshield before.

shoei · 10-05-2021, 09:40 PM

Quote:

Originally Posted by Murf993

Quote:

Originally Posted by wtwo3

I'm not a physicist but I'm feeling wild this evening. Let's do this....

Assumptions:
- power line height of 4.5 meters
- car windshield height of 1.4 meters
- goose weight of 6.5 kg
- the goose caused a 5cm deep indentation into the windshield

We will calculate a couple things:
- speed upon impact
- force of impact upon windshield

V = sqrt(2*g*h)
Where:
V = velocity at impact
g = acceleration (in this case gravity)
h = distance (in this case height)

So... v = sqrt(2*9.8*3.1) = 7.795 m/s = 17.4 mph

Next...

F = (m*g*h)/d
Where:
F = force
M = mass
G = gravity
H = height
D = distance (in this case the distance the goose moved the windshield as a result of the impact)

So... F = (6.5*9.8*3.1)/0.05 = 3,949 N = 887 lbs

Upon further research, the average force required to break a car windshield is 9,400 psi.

So what's the lesson here? Absolutely nothing.

I'm going to suggest that the goose was hit by the moving vehicle for two reasons, I've never seen a goose sitting on hydro wires or in a tree for that matter and two I've seen a goose go through a car windshield before.

The internet description said it hit a live wire and plummeted to the ground. Or rather, windshield.

kscarrol · 10-05-2021, 09:46 PM

Bird would need to grounded somehow so don’t see how a flying goose could be electrocuted…. Not to mention the associated,burns. Unless the bird broke its neck and fell. Might need another drink to consider this!

StripclubDJ · 10-05-2021, 10:43 PM

We will use the Impulse/Momentum Theorem. F
⋅∆𝑡=𝑚(𝑣𝑓−𝑣&#119894

⋅
∆
t
=
m
(
v
f
−
v
i
)
Let us assume that the bird is traveling head on to the car at a speed of +12m/s=Vi.
Let us assume the bird has a mass m=0.5kg
Lets us assume the bird after impact(the impulse) is now traveling (at least for a moment) -28m/s(-60mph)=Vf. In the opposite direction it was going.
Let us assume that the time during impulse is ∆t=0.010s.
Then the average force is F=0.5kg(-28m/s-12m/s)/(0.01s)=2,000Newtons.
Most birds that would hit a windshield would be less than .5kg.
Most impacts would not result in an opposite velocity vector i.e it would bounce off the windshield at an oblique angle.
If the last two sentences applied the force would be less.
If the time of impulse is less or the initial velocity of the bird is greater then the force increases.
2,000 N distributed over an area of impact of say 100cm

2

2
would result in 20N per sq. cm. about two kilograms of weight pressing on every sq. cm of glass. I do not believe that is enough to shatter the windshield. However, I do believe that the numbers I assumed are not unreasonable for the typical bird that might hit a car. The number that is highly suspect is my impact time, it could be less than that.
The poster can play with a greater mass or a greater initial velocity or a lesser time to increase the average force. Remember, this is just the average force there is actually a greater peak force occurring at the mid-time of impact. That is harder to determine without more measurements. Assume the peak force is 4000 N.
What I could find on the pressure to break a windshield was anywhere from 4000–16000 N/cm^2 and that depends on how long the pressure is applied to the glass.
Under the conditions I assumed I do not believe the windshield would shatter.
You would need a bigger and faster bird to get a shattered windshield.

JJ 911SC · 10-06-2021, 03:22 AM

.

Murf993 · 10-06-2021, 04:58 AM

Quote:

Originally Posted by shoei

The internet description said it hit a live wire and plummeted to the ground. Or rather, windshield.

Disregard my comment then.

Murf993 · 10-06-2021, 05:03 AM

Quote:

Originally Posted by StripclubDJ

We will use the Impulse/Momentum Theorem. F
⋅∆𝑡=𝑚(𝑣𝑓−𝑣&#119894

⋅
∆
t
=
m
(
v
f
−
v
i
)
Let us assume that the bird is traveling head on to the car at a speed of +12m/s=Vi.
Let us assume the bird has a mass m=0.5kg
Lets us assume the bird after impact(the impulse) is now traveling (at least for a moment) -28m/s(-60mph)=Vf. In the opposite direction it was going.
Let us assume that the time during impulse is ∆t=0.010s.
Then the average force is F=0.5kg(-28m/s-12m/s)/(0.01s)=2,000Newtons.
Most birds that would hit a windshield would be less than .5kg.
Most impacts would not result in an opposite velocity vector i.e it would bounce off the windshield at an oblique angle.
If the last two sentences applied the force would be less.
If the time of impulse is less or the initial velocity of the bird is greater then the force increases.
2,000 N distributed over an area of impact of say 100cm

2

2
would result in 20N per sq. cm. about two kilograms of weight pressing on every sq. cm of glass. I do not believe that is enough to shatter the windshield. However, I do believe that the numbers I assumed are not unreasonable for the typical bird that might hit a car. The number that is highly suspect is my impact time, it could be less than that.
The poster can play with a greater mass or a greater initial velocity or a lesser time to increase the average force. Remember, this is just the average force there is actually a greater peak force occurring at the mid-time of impact. That is harder to determine without more measurements. Assume the peak force is 4000 N.
What I could find on the pressure to break a windshield was anywhere from 4000–16000 N/cm^2 and that depends on how long the pressure is applied to the glass.
Under the conditions I assumed I do not believe the windshield would shatter.
You would need a bigger and faster bird to get a shattered windshield.

That goose is likely a lot more than .5KG.

From Wiki:

The male Canada goose usually weighs 2.6–6.5 kg (5.7–14.3 lb), averaging amongst all subspecies 3.9 kg (8.6 lb). The female looks virtually identical, but is slightly lighter at 2.4–5.5 kg (5.3–12.1 lb), averaging amongst all subspecies 3.6 kg (7.9 lb), and generally 10% smaller in linear dimensions than the male counterparts

Lady Jane · 10-06-2021, 05:47 AM

Attachment 2712845

cmyx6go · 10-06-2021, 06:25 AM

Quote:

Originally Posted by shoei

How you know to pack it in and call it a day.

Can't help but think about that WKRP episode.

10-05-2021, 05:18 PM	#35443
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10-05-2021, 09:46 PM	#35458
kscarrol Brigadier General 8912 Rep 4,107 Posts Drives: 2021 X3 M40i, 1974 2002 Tii Join Date: Jun 2010 Location: Greenville, SC iTrader: (0)	Bird would need to grounded somehow so don’t see how a flying goose could be electrocuted…. Not to mention the associated,burns. Unless the bird broke its neck and fell. Might need another drink to consider this! __________________ 2021 X3 M40i 1974 2002tii, Inka, 5 sp manual BMWCCA # 327475 Last edited by kscarrol; 10-05-2021 at 09:55 PM..
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10-05-2021, 10:43 PM	#35459
StripclubDJ Lieutenant Colonel 4100 Rep 1,612 Posts Drives: e92 m3 Join Date: May 2016 Location: calis iTrader: (2)	We will use the Impulse/Momentum Theorem. F ⋅∆𝑡=𝑚(𝑣𝑓−𝑣&#119894 ⋅ ∆ t = m ( v f − v i ) Let us assume that the bird is traveling head on to the car at a speed of +12m/s=Vi. Let us assume the bird has a mass m=0.5kg Lets us assume the bird after impact(the impulse) is now traveling (at least for a moment) -28m/s(-60mph)=Vf. In the opposite direction it was going. Let us assume that the time during impulse is ∆t=0.010s. Then the average force is F=0.5kg(-28m/s-12m/s)/(0.01s)=2,000Newtons. Most birds that would hit a windshield would be less than .5kg. Most impacts would not result in an opposite velocity vector i.e it would bounce off the windshield at an oblique angle. If the last two sentences applied the force would be less. If the time of impulse is less or the initial velocity of the bird is greater then the force increases. 2,000 N distributed over an area of impact of say 100cm 2 2 would result in 20N per sq. cm. about two kilograms of weight pressing on every sq. cm of glass. I do not believe that is enough to shatter the windshield. However, I do believe that the numbers I assumed are not unreasonable for the typical bird that might hit a car. The number that is highly suspect is my impact time, it could be less than that. The poster can play with a greater mass or a greater initial velocity or a lesser time to increase the average force. Remember, this is just the average force there is actually a greater peak force occurring at the mid-time of impact. That is harder to determine without more measurements. Assume the peak force is 4000 N. What I could find on the pressure to break a windshield was anywhere from 4000–16000 N/cm^2 and that depends on how long the pressure is applied to the glass. Under the conditions I assumed I do not believe the windshield would shatter. You would need a bigger and faster bird to get a shattered windshield.
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